There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0, 0) after it completes its moves.

The move sequence is represented by a string, and the character moves[i] represents its ith move. Valid moves are R (right), L (left), U (up), and D (down). If the robot returns to the origin after it finishes all of its moves, return true. Otherwise, return false.

Note: The way that the robot is “facing” is irrelevant. “R” will always make the robot move to the right once, “L” will always make it move left, etc. Also, assume that the magnitude of the robot’s movement is the same for each move.

Example 1:

Input: “UD” Output: true Explanation: The robot moves up once, and then down once. All moves have the same magnitude, so it ended up at the origin where it started. Therefore, we return true.

Example 2:

Input: “LL” Output: false Explanation: The robot moves left twice. It ends up two “moves” to the left of the origin. We return false because it is not at the origin at the end of its moves.

題意：

機器人可以上下左右移動，起始點（0，0），執行一串指令後是否能回到原點

知識點：

再次記憶：for(char move : moves.toCharArray()){

bug:

在最後判定條件總想省事不寫兩個都為0

class Solution {
    public boolean judgeCircle(String moves) {
        int level = 0;
        int vertical = 0;
        for(char move : moves.toCharArray()){
            if(move == 'U'){
                vertical++;
            }else if(move == 'D'){
                vertical--;
            }else if(move == 'L'){
                level--;
            }else{
                level++;
            }
        }
        if((vertical == 0) && (level == 0)){
            return true;
        }else{
            return false;
        }
    }
}