1038 Recover the Smallest Number (30 分)
1038 Recover the Smallest Number (30 分)
Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given { 32, 321, 3214, 0229, 87 }, we can recover many numbers such like 32-321-3214-0229-87 or 0229-32-87-321-3214 with respect to different orders of combinations of these segments, and the smallest number is 0229-321-3214-32-87.
Input Specification:
Each input file contains one test case. Each case gives a positive integer N (≤104) followed by N number segments. Each segment contains a non-negative integer of no more than 8 digits. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the smallest number in one line. Notice that the first digit must not be zero.
Sample Input:
5 32 321 3214 0229 87
Sample Output:
22932132143287
呃呃呃呃呃以前寫過,但是感覺自己還是不開竅 直接比較字串a+b和b+a哪個比較小即可
程式碼:
#include<bits/stdc++.h> using namespace std; vector<string>vec; bool cmp(string a, string b){ return a + b < b + a; } int main() { int n; scanf("%d", &n); char str[10]; for(int i = 0 ; i < n ; i ++) { scanf("%s",str); vec.push_back(str); } sort(vec.begin(), vec.end(), cmp); string s = "",t = ""; for(int i = 0 ; i < vec.size(); i ++) s += vec[i]; while(s.empty() == 0 && s.at(0) == '0') s.replace(0,1,""); if(s.empty() == true) cout<<0<<endl; else cout<<s<<endl; return 0; }