List Sorting (25)
阿新 • • 發佈:2018-12-01
List Sorting (25)
時間限制 1000 ms 記憶體限制 65536 KB 程式碼長度限制 100 KB 判斷程式 Standard (來自 小小)
題目描述
Excel can sort records according to any column. Now you are supposed to imitate this function.
輸入描述:
Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).
輸出描述:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.
輸入例子:
3 1 000007 James 85 000010 Amy 90 000001 Zoe 60
輸出例子:
000001 Zoe 60 000007 James 85 000010 Amy 90
#include<stdio.h> #include<iostream> #include<string.h> #include<algorithm> using namespace std; struct student{ char name[10]; int id; int grade; }s[100005]; bool cmp1(struct student x,struct student y) { return x.id<y.id; } bool cmp2(struct student x,struct student y) { if(strcmp(x.name,y.name)!=0) return strcmp(x.name,y.name)<0; else return x.id<y.id; } bool cmp3(struct student x,struct student y) { if(x.grade!=y.grade) return x.grade<y.grade; else return x.id<y.id; } int main() { int m,n,i,j; scanf("%d%d",&n,&m); for(i=0;i<n;i++) cin>>s[i].id>>s[i].name>>s[i].grade; if(m==1) sort(s,s+n,cmp1); else if(m==2) sort(s,s+n,cmp2); else sort(s,s+n,cmp3); for(i=0;i<n;i++) printf("%06d %s %d\n",s[i].id,s[i].name,s[i].grade); return 0; }
非常簡單的一道題,就是審題的時候不認真,結構體比較的時候容易出錯,還有就是id不能用字串表示,要用int 型,最後輸出的時候控制一下就好。