Problem Description
Given a positive integer N, you should output the most right digit of N^N.
 

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
 

Output
For each test case, you should output the rightmost digit of N^N.
 

Sample Input
2 3 4
 

Sample Output
7 6
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7. In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.

題意：求N^N。

思路：快速冪裸題。注意一下變數型別。

 1
 
 #include<iostream>
 2 using namespace std;
 3 int qm(long long a){
 4     int  ans=1;
 5     long long b=a;
 6     a=a%10;
 7     while(b){      
 8         if(b&1) ans=(ans*a)%10;
 9         b=b>>1;
10         a=(a*a)%10;
11     }    
12     return ans;
13 }
14 
15 int main(){
16     int
 
 T,N;
17     cin>>T;
18     while(T--){
19         cin>>N;
20         cout<<qm(N)<<endl;
21     }
22     return 0;
23 }