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leetcode-有效的數獨

判斷一個 9x9 的數獨是否有效。只需要根據以下規則,驗證已經填入的數字是否有效即可。

數字 1-9 在每一行只能出現一次。
數字 1-9 在每一列只能出現一次。
數字 1-9 在每一個以粗實線分隔的 3x3 宮內只能出現一次。

上圖是一個部分填充的有效的數獨。

數獨部分空格內已填入了數字,空白格用 ‘.’ 表示。

示例 1:

輸入:
[
  ["5","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]
輸出: true

示例 2:

輸入:
[
  ["8","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]
輸出: false

解釋: 除了第一行的第一個數字從 5 改為 8 以外,空格內其他數字均與 示例1 相同。
但由於位於左上角的 3x3 宮內有兩個 8 存在, 因此這個數獨是無效的。
說明:

一個有效的數獨(部分已被填充)不一定是可解的。
只需要根據以上規則,驗證已經填入的數字是否有效即可。
給定數獨序列只包含數字 1-9 和字元 ‘.’ 。
給定數獨永遠是 9x9 形式的。

程式碼


/**
 * @param {character[][]} board
 * @return {boolean}
 */
var isValidSudoku = function(board) {
    let rows =
{}; let ranks = {}; let react = {}; let result = true; for(let n=0;n<board.length;n++){ for(let m=0;m<board[n].length;m++){ let value = board[n][m] if(value != '.'){ if(!rows[n]){ rows[n] ={} } if(!ranks[m]){ ranks[m]={} } //條件一 if(!rows[n][value]){ rows[n][value] = true }else{ result = false; } //條件二 if(!ranks[m][value]){ ranks[m][value] = true; }else{ result = false; } //條件三 let rowsN = Math.ceil((n+1)/3); let ranksM = Math.ceil((m+1)/3); if(!react[rowsN]){ react[rowsN] = {} } if( !react[rowsN][ranksM] ){ react[rowsN][ranksM] = {} } if(!react[rowsN][ranksM][value]){ react[rowsN][ranksM][value] = true }else{ result = false; } } } } return result };