水題～

用string特別方便

#include <iostream>
#include <cstring>
#include <string>
#include <sstream>
#include <string>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <vector>
#define maxn 1005
#define INF 0x3f3f3f3f
#define EPS 1e-6
#define
 
 pi acos(-1.0)
using namespace std;
typedef long long ll;
string name,pass;
string ansn[maxn],ansp[maxn];
int main()
{
    int n;
    cin>>n;
    int cnt=0;
    for(int i=0;i<n;i++)
    {
        cin>>name>>pass;
        int len=pass.length();
        int mark=0;
        for(int j=0;j<len;j++)
        {
            
 
if(pass[j]=='1')
            {
                pass[j]='@';
                mark=1;
            }
            else if(pass[j]=='0')
            {
                mark=1;
                pass[j]='%';
            }
            else if(pass[j]=='l')
            {
                mark=1;
                pass[j]
 
='L';
            }
            else if(pass[j]=='O')
            {
                mark=1;
                pass[j]='o';
            }
        }
        if(mark)
        {
            ansn[cnt]=name;
            ansp[cnt]=pass;
            cnt++;
        }
    }
    if(cnt==0)
    {
        if(n==1)
            cout<<"There is 1 account and no account is modified"<<endl;
        else
            cout<<"There are "<<n<<" accounts and no account is modified"<<endl;
    }
    else
    {
        cout<<cnt<<endl;
        for(int i=0;i<cnt;i++)
        {
            cout<<ansn[i]<<" "<<ansp[i]<<endl;
        }
    }
    return 0;
}