[leetcode] Range Sum Query - Immutable

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leetcode Range Sum Query - Immutable

leetcode Range Sum Query - Immutable  https://leetcode.com/problems/range-sum-query-immutable/ 在指定範圍內的累加和： 動態規劃 使用一個數組記錄從0到當前位置的累加和。 i-j

（leetcode題解）Range Sum Query - Immutable

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LeetCode : 303. 區域和檢索 - 陣列不可變（Range Sum Query - Immutable）解答

303. 區域和檢索 - 陣列不可變 給定一個整數陣列 nums，求出陣列從索引 i 到 j (i ≤ j) 範圍內元素的總和，包含 i, j 兩點。 示例： 給定 nums = [-2, 0, 3, -5, 2, -1]，求和函式為 sumRange() su

[LeetCode] 304. Range Sum Query 2D - Immutable 二維區域和檢索 - 不可變 303. Range Sum Query - Immutable [LeetCode] 303. Range Sum Query - Immutable 區域和檢索 - 不可變

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner

【LeetCode】range-sum-query-immutable

題目描述： Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2,

LeetCode演算法題-Range Sum Query Immutable（Java實現）

這是悅樂書的第204次更新，第214篇原創 01 看題和準備 今天介紹的是LeetCode演算法題中Easy級別的第70題（順位題號是303）。給定整數陣列nums，找到索引i和j（i≤j）之間的元素之和，包括端點。例如： 給定nums = [-2,0,3,-5,2,-1]

303. Range Sum Query - Immutable 數組範圍求和 - 不變

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303. Range Sum Query - Immutable

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Range Sum Query - Immutable

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[LeetCode] Range Sum Query

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updat

[LeetCode] Range Sum Query 2D

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, c

303.Range Sum Query Immutable

303. Range Sum Query - Immutable(數組區間和)

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[leetcode]304. Range Sum Query 2D - Immutable二維區間求和 - 不變

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[leetcode]304. Range Sum Query 2D - Immutable

整體的思路一樣。就是dp這個怎麼求沒想出來 class NumMatrix { private int[][] dp; public NumMatrix(int[][] matrix) { if (matrix.length == 0 || m

LeetCode - 307. Range Sum Query - Mutable

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leetcode之Range Sum Query

題目： 給定一個整數陣列  nums，求出陣列從索引 i 到 j  (i ≤ j) 範圍內元素的總和，包含 i,  j 兩點。 示例： 給定 nums = [-2, 0, 3, -5, 2, -1]，求和函式為 sumRange() sumRange(0, 2) -&

LeetCode#303 Range Sum Query

1、利用動態規劃思想，sum(i, j) 實際上是sum(0, j) - sum(0, i-1) 。 2、構造一個逐次累加和的陣列，返回i、j兩項相減結果即可。 class NumArray { public: NumArray(vector<in

307. Range Sum Query - Mutable

indices mutable counter num index 二維 mod mar bit Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j