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[leetcode]494. Target Sum

[leetcode]494. Target Sum


Analysis

完了完了 真的要找不到工作了!!!!!蒼了天了!!!—— [每天刷題並不難0.0]

You are given a list of non-negative integers, a1, a2, …, an, and a target, S. Now you have 2 symbols + and -. For each integer, you should choose one from + and - as its new symbol.
Find out how many ways to assign symbols to make sum of integers equal to target S.
在這裡插入圖片描述


在討論區看到的一個大神的分析,很強啊!!!連結:
https://leetcode.com/problems/target-sum/discuss/97334/Java-(15-ms)-C%2B%2B-(3-ms)-O(ns)-iterative-DP-solution-using-subset-sum-with-explanation
counter部分主要用了416題的方法:https://blog.csdn.net/weixin_32135877/article/details/84847236

Implement

class Solution {
public:
    int findTargetSumWays(
vector<int>& nums, int S) { int sum = accumulate(nums.begin(), nums.end(), 0); if(sum < S || ((sum+S)&1)) return 0; return counter(nums, (sum+S)>>1); } int counter(vector<int>& nums, int target){ vector<int> dp(
target+1, 0); dp[0] = 1; for(int num:nums){ for(int i=target; i>=num; i--) dp[i] += dp[i-num]; } return dp[target]; } };