參考了種種演算法，最後的成品能推算1950~2050年間所有的年月日時干支，但是在春節前後可能不準。 NOIP賽前寫下的小程式，用以放鬆心情，大家如果春節前後需要排盤還是百度一下比較好。 耿直的我直接上程式碼好了：

/*
	Name: 四柱推算小程式
	Copyright: JLZ from CDQZ 
	Author: 懷塵先森 
	Date: 05/11/18 15:37
	Description: 請保留此檔案頭 
*/
#include<iostream>
#include<iomanip>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<cmath> 
#include<ctime>
#include<Windows.h>
#include<WINBASE.H>
using namespace std;
const char *cTianGan[] = {"庚","辛","壬","癸","甲","乙","丙","丁","戊","己",};
const char *cDiZhi[] = {"申","酉","戌","亥","子","醜","寅","卯","辰","巳","午","未"};
const int yearfixday[101]={31,36,42,47,52,57,3,8,13,18,24,29,34,39,45,50,55,0,6,11,16,21,27,32,37,42,48,53,58,3,9,14,19,24,30,35,40,45,51,56,1,6,12,17,22,27,33,38,43,48,54,59,4,9,15,20,25,30,36,41,46,51,57,2,7,12,18,23,28,33,39,44,49,54,0,5,10,15,21,26,31,36,42,47,52,57,3,8,13,18,24,29,34,39,45,50,55,0,6,11};
const int monfixday[13]={0,6,37,0,31,1,32,2,33,4,34,5,35};
int main()
{
	int year=0,month=0,monTianGan=0,day=0,dayGanZhi=0,hour,hourTianGan=0;
	float fhour=0;
	printf("格式:如2018-11-4-18.50\n年-月-日-時\n");
	scanf("%d-%d-%d-%f",&year,&month,&day,&fhour);
	if (fhour>=23)
	{
		cout<<"請注意：晚上超過23點應該記為下一天\n";
		scanf("%d-%d-%d-%f",&year,&month,&day,&fhour);
	}
	if (month<=2) year--;
	cout<<cTianGan[year%10]<<cDiZhi[year%12]<<"年"<<endl;
	switch  (year%10)
	{
		case 4:case 9:monTianGan=5;break;
		case 5:case 0:monTianGan=7;break;
		case 6:case 1:monTianGan=-1;break;
		case 2:case 7:monTianGan=1;break;
		case 3:case 8:monTianGan=3;break;
		default: cout<<"erro code:2\n";break;
	}
	monTianGan+=month-1;
	cout<<cTianGan[monTianGan%10]<<cDiZhi[(month+4)%12]<<"月"<<endl;
	dayGanZhi=yearfixday[year-1950]+monfixday[month]+day;
	cout<<cTianGan[(dayGanZhi+3)%10]<<cDiZhi[(dayGanZhi+3)%12]<<"日"<<endl;
	hour=(fhour+1)/2;
	switch ((dayGanZhi+3)%10)
	{
		case 4:case 9:hourTianGan=4;break;
		case 5:case 0:hourTianGan=6;break;
		case 6:case 1:hourTianGan=8;break;
		case 2:case 7:hourTianGan=0;break;
		case 3:case 8:hourTianGan=2;break;
		default: cout<<"erro code:4\n";break;
	}
	hourTianGan+=hour; 
	cout<<cTianGan[hourTianGan%10]<<cDiZhi[(hour+4)%12]<<"時"<<endl;
	getchar();
	return 0;
}