LeetCode-Guess Number Higher or Lower
阿新 • • 發佈:2018-12-19
Description: We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I’ll tell you whether the number is higher or lower.
You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):
-1 : My number is lower 1 : My number is higher 0 : Congrats! You got it!
Example :
- Input: n = 10, pick = 6
- Output: 6
題意:模擬一個猜數字的遊戲,給定一個範圍[1,n],猜測在這個範圍內的一個數字,每一次的猜測都會給出你所猜的是大了,小了,還是正確找到那個數字,返回所要猜測的那個數字;
解法:根據題意相當於讓我們實現二分查詢,每次猜測一個數字後判斷是否是要找的那個數,或者是偏大了,或者是偏小了,總之,根據guess函式的返回值,我們來實現二分查詢;
Java
/* The guess API is defined in the parent class GuessGame. @param num, your guess @return -1 if my number is lower, 1 if my number is higher, otherwise return 0 int guess(int num); */ public class Solution extends GuessGame { public int guessNumber(int n) { long low = 1; long high = n; while (low <= high) { long mid = (low + high) / 2; int gus = guess((int)mid); if (gus == 0) return (int)mid; else if (gus == -1) high = mid - 1; else low = mid + 1; } return -1; } }