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[LeetCode] Guess Number Higher or Lower 猜數字大小

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-11, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!

Example:

n = 10, I pick 6.

Return 6.

這道題是一道典型的猜價格的問題,根據對方說高了還是低了來縮小範圍,最簡單快速的方法就是折半搜尋法,原理很簡單,參見程式碼如下:

// Forward declaration of guess API.
// @param num, your guess
// @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
int guess(int num);

class Solution {
public
: int guessNumber(int n) { if (guess(n) == 0) return n; int left = 1, right = n; while (left < right) { int mid = left + (right - left) / 2, t = guess(mid); if (t == 0) return mid; else if (t == 1) left = mid; else right = mid; }
return left; } };

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