G a+b+c+d=?
阿新 • • 發佈:2019-01-06
G | a+b+c+d=? |
連結:https://ac.nowcoder.com/acm/contest/338/G
來源:牛客網
題目描述
This is a very simple problem! Your only job is to calculate a + b + c + d!輸入描述:
There are several cases.
In the first line, there is a single integer T.(T <= 200)
In the next T lines, each line contains four integers a, b, c and d(-2^61 <= a,b,c,d <=2^61)
輸出描述:
output T lines.示例1
Each line output one integer represent the answer of a + b + c + d
輸入
複製1 1 2 3 4
輸出
複製10
double || long double 都可以
#include<stdio.h> int main() { int t; scanf(View Code"%d",&t); while(t--) { long double a,b,c,d; scanf("%LF%LF%LF%LF",&a,&b,&c,&d); long double sum = 0; sum = a+b+c+d; printf("%.0LF\n",sum); } }
py過的
n=int(input()) for i in range(n): a,b,c,dView Code= map(int,input().split()) print(a+b+c+d)