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G a+b+c+d=?

G a+b+c+d=?

連結:https://ac.nowcoder.com/acm/contest/338/G
來源:牛客網

題目描述

This is a very simple problem! Your only job is to calculate a + b + c + d!

輸入描述:

There are several cases.

In the first line, there is a single integer T.(T <= 200)

In the next T lines, each line contains four integers a, b, c and d(-2^61 <= a,b,c,d <=2^61)

輸出描述:

output T lines.

Each line output one integer represent the answer of a + b + c + d
示例1

輸入

複製
1
1 2 3 4

輸出

複製
10

double || long double 都可以
#include<stdio.h>
int main()
{
    int t;
    scanf(
"%d",&t); while(t--) { long double a,b,c,d; scanf("%LF%LF%LF%LF",&a,&b,&c,&d); long double sum = 0; sum = a+b+c+d; printf("%.0LF\n",sum); } }
View Code

py過的

n=int(input())
for i in range(n):
        a,b,c,d 
= map(int,input().split()) print(a+b+c+d)
View Code