【組合&元素和】3Sum Closest
阿新 • • 發佈:2019-01-10
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
解法:先固定一個值轉化成二元素和問題
public class Solution { public int threeSumClosest(int[] num, int target) { Arrays.sort(num); int len = num.length; int a = Integer.MAX_VALUE; int b = 0; for(int i=0; i<len; i++){ int p = i+1, q = len-1; while(p < q){ int t = num[i] + num[p] + num[q]; if(t == target) return t; int ta = Math.abs(t - target); if(ta < a){ a = ta; b = t; } if(t < target) p++; else q--; } } return b; } }