資料結構之基於圖的廣度優先搜尋,判斷無向圖的連通性
阿新 • • 發佈:2019-02-20
#include <iostream>
using namespace std;
struct LinkNode
{
int data;
LinkNode *next;
};
struct LinkQueue
{
LinkNode *front;
LinkNode *rear;
};
void init(LinkQueue *&Q)
{
Q=new LinkQueue;
Q->front=new LinkNode;
Q->front->next=0;
Q->rear=Q->front;
}
bool isEmpty(LinkQueue *Q)
{
return Q->rear==Q->front;
}
bool isNotEmpty(LinkQueue *Q)
{
return Q->rear!=Q->front;
}
void push(LinkQueue *&Q,int e)
{
LinkNode *p=new LinkNode;
p->data=e;
p->next=0;
Q->rear->next=p;
Q->rear=p;
}
int pop(LinkQueue *&Q)
{
if(isNotEmpty(Q))
{
LinkNode *p=Q->front->next;
int d=p->data;
Q->front->next=p->next;
if(Q->rear==p)
Q->rear=Q->front;
delete p;
return d;
}
}
const int n=5;
int G[n][n]={ {0,1,0,0,0},
{1,0,1,0,1},
{0,1,0,0,1},
{0,0,0,0,0},
{0,1,1,0,0}, };
int visited[n];
void init()
{
for(int v=1;v<=n;v++)
visited[v]=0;
}
bool BFS(LinkQueue *&Q,int v)
{
visited[v]=1;
push(Q,v);
int c=0;
while(isNotEmpty(Q))
{
v=pop(Q);
c++;
cout<<"v"<<v+1<<endl;
for(int w=0;w<n;w++)
{
if(G[v][w] && (!visited[w]))
{
visited[w]=1;
push(Q,w);
}
}
}
if(c==n)
return true;
return false;
}
int main()
{
LinkQueue *Q;
init(Q);
init();
if(BFS(Q,0))
cout<<"ok"<<endl;
else
cout<<"no"<<endl;
return 0;
}
using namespace std;
struct LinkNode
{
int data;
LinkNode *next;
};
struct LinkQueue
{
LinkNode *front;
LinkNode *rear;
};
void init(LinkQueue *&Q)
{
Q=new LinkQueue;
Q->front=new LinkNode;
Q->front->next=0;
Q->rear=Q->front;
}
bool isEmpty(LinkQueue *Q)
{
return Q->rear==Q->front;
}
bool isNotEmpty(LinkQueue *Q)
{
return Q->rear!=Q->front;
}
void push(LinkQueue *&Q,int e)
{
LinkNode *p=new LinkNode;
p->data=e;
p->next=0;
Q->rear->next=p;
Q->rear=p;
}
int pop(LinkQueue *&Q)
{
if(isNotEmpty(Q))
{
LinkNode *p=Q->front->next;
int d=p->data;
Q->front->next=p->next;
if(Q->rear==p)
Q->rear=Q->front;
delete p;
return d;
}
}
const int n=5;
int G[n][n]={ {0,1,0,0,0},
{1,0,1,0,1},
{0,1,0,0,1},
{0,0,0,0,0},
{0,1,1,0,0}, };
int visited[n];
void init()
{
for(int v=1;v<=n;v++)
visited[v]=0;
}
bool BFS(LinkQueue *&Q,int v)
{
visited[v]=1;
push(Q,v);
int c=0;
while(isNotEmpty(Q))
{
v=pop(Q);
c++;
cout<<"v"<<v+1<<endl;
for(int w=0;w<n;w++)
{
if(G[v][w] && (!visited[w]))
{
visited[w]=1;
push(Q,w);
}
}
}
if(c==n)
return true;
return false;
}
int main()
{
LinkQueue *Q;
init(Q);
init();
if(BFS(Q,0))
cout<<"ok"<<endl;
else
cout<<"no"<<endl;
return 0;
}