1 const int maxn = 10000;
 2 #define _for(i,a,b) for(int i = (a);i < (b);i ++)
 3 typedef long long ll;
 4 
 5 
 6 class Solution
 7 {
 8     public:
 9         int t[60][60];
10         int s[60][60];
11         int weight[60];
12         int N;
13         int get_weight(const int a, const int
 
 b, const int c)
14         {
15             return weight[a] * weight[b] * weight[c];
16         }
17         int minScoreTriangulation(vector<int>& A)
18         {
19             int N = A.size();
20             _for(i,0,A.size())
21                 weight[i] = A[i];
22             int
 
 i,r,k,j;
23             int min;
24 
25             for (i = 1; i < N; i++)
26             {
27                 t[i][i] = 0;
28             }
29 
30             for (r = 2; r < N; r++)
31             {
32                 for (i = 1; i < N-r+1; i++)
33                 {
34                     j = i + r -1
 
;
35                     min = INT_MAX;
36                     for (k = i; k < j; k++)
37                     {
38                         t[i][j] = t[i][k] + t[k+1][j] + get_weight(i-1,k,j);
39                         if (t[i][j] < min)
40                         {
41                             min = t[i][j];
42                             s[i][j] = k;
43                         }
44                     }
45                     t[i][j] = min;
46                 }
47             }
48             return t[1][N-1];
49         }
50 };

多邊形三角剖分，DP走起來

Leetcode-5047 Minimum Score Triangulation of Polygon(多邊形三角剖分的最低得分)