python實現簡單井字棋遊戲
阿新 • • 發佈:2020-03-04
井字棋,英文名叫Tic-Tac-Toe,是一種在3*3格子上進行的連珠遊戲,和五子棋類似,由於棋盤一般不畫邊框,格線排成井字故得名。遊戲需要的工具僅為紙和筆,然後由分別代表O和X的兩個遊戲者輪流在格子裡留下標記(一般來說先手者為X),任意三個標記形成一條直線,則為獲勝。
遊戲的難點在於,如何判斷連線成了一條線;橫、豎、斜三個方向;
遊戲的程式碼:
#!/usr/bin/env python3 # -*- coding:utf-8 -*- u''' Created on 2019年4月13日 @author: wuluo ''' __author__ = 'wuluo' __version__ = '1.0.0' __company__ = u'重慶交大' __updated__ = '2019-04-13' # 建立井字棋的程式 def initBoard(): global board # 呼叫全域性的board board = [None] * 3 print("井字棋:") for i in range(len(board)): board[i] = ["+ "] * 3 # 列印井字棋的程式 def printBoard(): global board for i in range(len(board)): for j in range(len(board[i])): print(board[i][j],end=" ") print("") # 開始下棋的程式 def startGame(): global board player = 0 while isGameContinue(): if player <= 8: if player % 2 == 0: # 甲方下棋 print("==>黑方下棋") if not playChess("x"): continue else: # 乙方下棋 print("==>白方下棋") if not playChess("○"): continue player += 1 else: print("平局") break def playChess(chess): # 獲取位置 x = int(input("==> X=")) - 1 y = int(input("==> Y=")) - 1 if board[x][y] == "+ ": board[x][y] = chess printBoard() return True # 落子成功 else: print("==> 已有棋子 請重新落子\a") printBoard() return False # 落子失敗 def isGameContinue(): for i in range(len(board)): for j in range(len(board[i])): if board[i][j] != "+ ": # 橫向 if j == 0: if board[i][j] == board[i][j + 1] == board[i][j + 2]: whoWin(i,j) return False # 豎向 if i == 0: if board[i][j] == board[i + 1][j] == board[i + 2][j]: whoWin(i,j) return False # 正斜 if i == 0 and j == 0: if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]: whoWin(i,j) return False # 反斜 if i == 2 and j == 0: if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]: whoWin(i,j) return False return True def whoWin(i,j): if board[i][j] == "x": print("黑方勝!") else: print("白方勝!") for i in range(3): print("win") class main(): board = [] initBoard() printBoard() startGame() if __name__ == "__main__": main()
遊戲結果:
還有一種結果是平局:
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