技術標籤：演算法題解java演算法

著重考慮資料型別，邊界值

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        long a = 1L, b = 1L, result, sum = 0L;
        // 如果為前2項則將結果設為1
        if (n == 1 || n == 2
 
) {
            result = 1L;
        } else {
            while (n > 2) {
                sum = a + b;
                a = b;
                b = sum % 10007; // 取sum的模數
                n--;
            }
            result = sum % 10007; // 再次取sum的模數，防止最後一次a+b的值超出10007
        }
        // 輸出結果
        System.
 
out.println(result);
    }
    
}