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CF821C Okabe and Boxes

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思路:

模擬。不一致的時候直接清空棧即可。

實現:

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <vector>
 4 using namespace std;
 5 int main()
 6 {
 7     vector<int> v;
 8     int n, cnt = 1, ans = 0;
 9     string s;
10     cin >> n;
11     for (int i = 0; i < 2 * n; i++)
12     {
13 cin >> s; 14 if (s[0] == a) 15 { 16 int tmp; 17 scanf("%d", &tmp); 18 v.push_back(tmp); 19 } 20 else 21 { 22 if (!v.empty()) 23 { 24 if (v[v.size() - 1] == cnt) v.pop_back();
25 else 26 { 27 v.clear(); 28 ans++; 29 } 30 } 31 cnt++; 32 } 33 } 34 printf("%d\n", ans); 35 return 0; 36 }

CF821C Okabe and Boxes