1. 程式人生 > >bzoj2768: [JLOI2010]冠軍調查(雙倍經驗最小割)

bzoj2768: [JLOI2010]冠軍調查(雙倍經驗最小割)

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2768: [JLOI2010]冠軍調查

題目:傳送門

題解:
   雙倍經驗(1934)

代碼:

#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
#define qread(x) x=read()
using namespace std;
inline int read()
{
    int f=1,x=0;char ch;
    while(ch<0 || ch>
9){if(ch==-)f=-1;ch=getchar();} while(ch>=0 && ch<=9){x=x*10+ch-0;ch=getchar();} return f*x; } struct node { int x,y,c,next,other; }a[210000];int len,last[110000]; int n,m,st,ed; void ins(int x,int y,int c) { int k1,k2; k1=++len; a[len].x=x;a[len].y=y;a[len].c=c; a[len].next
=last[x];last[x]=len; k2=++len; a[len].x=y;a[len].y=x;a[len].c=0; a[len].next=last[y];last[y]=len; a[k1].other=k2; a[k2].other=k1; } int list[110000],h[110000],head,tail; bool bt_h() { memset(h,0,sizeof(h));h[st]=1; list[1]=st;head=1;tail=2; while(head!=tail) {
int x=list[head]; for(int k=last[x];k;k=a[k].next) { int y=a[k].y; if(h[y]==0 && a[k].c>0) { h[y]=h[x]+1; list[tail++]=y; } } head++; } if(h[ed]>0)return true; return false; } int find_flow(int x,int flow) { if(x==ed)return flow; int s=0,t; for(int k=last[x];k;k=a[k].next) { int y=a[k].y; if(h[y]==h[x]+1 && a[k].c>0 && s<flow) { s+=t=find_flow(y,min(a[k].c,flow-s)); a[k].c-=t;a[a[k].other].c+=t; } } if(s==0)h[x]=0; return s; } int main() { qread(n);qread(m); len=0;memset(last,0,sizeof(last)); st=110000-2;ed=st+1; for(int i=1;i<=n;i++) { int x;qread(x); if(x==1)ins(st,i,1); else ins(i,ed,1); } for(int i=1;i<=m;i++) { int x,y; qread(x);qread(y); ins(x,y,1); ins(y,x,1); } int ans=0; while(bt_h())ans+=find_flow(st,999999999); printf("%d\n",ans); return 0; }

bzoj2768: [JLOI2010]冠軍調查(雙倍經驗最小割)