題目傳送門

題意：給出一個$N$個點、$M$條邊的無向圖，找出其中的點，滿足去掉該點與和它相連的邊之後，這個圖會變成一棵樹。$N , M \leq 10^5$

說是毒瘤，真的不毒瘤

思考一下，我們需要找的就是度為$M - (N - 1 - 1)$且不是割點的點，直接tarjan即可

想起來在某luogu題解裏把tarjan寫成targan

 1 #include<bits/stdc++.h>
 2 #define MAXN 100001
 3 using namespace std;
 4 
 5 inline int read(){
 6     int a = 0;
 7     char
 
 c = getchar();
 8     while(!isdigit(c))
 9         c = getchar();
10     while(isdigit(c)){
11         a = (a << 3) + (a << 1) + (c ^ ‘0‘);
12         c = getchar();
13     }
14     return a;
15 }
16 
17 struct Edge{
18     int end , upEd;
19 }Ed[MAXN << 1];
20 
21 int head[MAXN] , dfn[MAXN] , low[MAXN] , in
 
[MAXN] , ts , cntEd , N , M;
22 bool vis[MAXN];
23 
24 inline void addEd(int a , int b){
25     Ed[++cntEd].end = b;
26     Ed[cntEd].upEd = head[a];
27     head[a] = cntEd;
28     in[a]++;
29 }
30 
31 void tarjan(int a , int fa){
32     dfn[a] = low[a] = ++ts;
33     int ch = 0;
34     for(int i = head[a] ; i ; i = Ed[i].upEd)
 
35         if(Ed[i].end != fa)
36             if(!dfn[Ed[i].end]){
37                 tarjan(Ed[i].end , a);
38                 low[a] = min(low[Ed[i].end] , low[a]);
39                 ch++;
40                 if(low[Ed[i].end] >= dfn[a] && a != 1)
41                     vis[a] = 1;
42             }
43             else
44                 low[a] = min(low[a] , dfn[Ed[i].end]);
45     if(a == 1 && ch >= 2)
46         vis[a] = 1;
47 }
48 
49 int main(){
50     N = read();
51     M = read();
52     for(int i = 1 ; i <= M ; i++){
53         int a = read() , b = read();
54         addEd(a , b);
55         addEd(b , a);
56     }
57     tarjan(1 , 0);
58     int ans = 0;
59     for(int i = 1 ; i <= N ; i++)
60         if(in[i] == M - N + 2 && !vis[i])
61             ans++;
62     cout << ans << endl;
63     for(int i = 1 ; i <= N ; i++)
64         if(in[i] == M - N + 2 && !vis[i])
65             cout << i << ‘ ‘;
66     return 0;
67 }

UOJ#67 新年的毒瘤 tarjan