滴答滴答---題目連結 

There are two standard ways to represent a graph G=(V,E)G=(V,E), where VV is a set of vertices and EE is a set of edges; Adjacency list representation and Adjacency matrix representation.

An adjacency-list representation consists of an array Adj[|V|]Adj[|V|] of |V||V| lists, one for each vertex in VV. For each u∈Vu∈V, the adjacency list Adj[u]Adj[u] contains all vertices vv such that there is an edge (u,v)∈E(u,v)∈E. That is, Adj[u]Adj[u] consists of all vertices adjacent to uu in GG.

An adjacency-matrix representation consists of |V|×|V||V|×|V| matrix A=aijA=aij such that aij=1aij=1 if (i,j)∈E(i,j)∈E, aij=0aij=0 otherwise.

Write a program which reads a directed graph GG represented by the adjacency list, and prints its adjacency-matrix representation. GG consists of n(=|V|)n(=|V|) vertices identified by their IDs 1,2,..,n1,2,..,nrespectively.

Input

In the first line, an integer nn is given. In the next nn lines, an adjacency list Adj[u]Adj[u] for vertex uu are given in the following format:

uu kk v1v1 v2v2 ... vkvk

uu is vertex ID and kk denotes its degree. vivi are IDs of vertices adjacent to uu.

Output

As shown in the following sample output, print the adjacent-matrix representation of GG. Put a single space character between aijaij.

Constraints

• 1≤n≤1001≤n≤100

Sample Input

4
1 2 2 4
2 1 4
3 0
4 1 3

Sample Output

0 1 0 1
0 0 0 1
0 0 0 0
0 0 1 0

#include <iostream>
#include<stdio.h>
#include<string.h>
using namespace std;
const int maxn=101;
int e[maxn][maxn];
int main()
{
    int n,u,k,v;
    scanf("%d",&n);
    for(int i=0; i<n; i++)
        for(int j=0; j<n; j++)
            e[i][j]=0;
    for(int i=0; i<n; i++)
    {
        scanf("%d%d",&u,&k);
        u--;
        for(int j=0; j<k; j++)
        {
            scanf("%d",&v);
            v--;//轉化為0起點
            e[u][v]=1;
        }
    }
    for(int i=0; i<n; i++)
    {
        for(int j=0; j<n; j++)
        {
            if(j)printf(" ");
            printf("%d",e[i][j]);
        }
        cout<<endl;
    }
    return 0;
}