IoU:Intersection over Union
阿新 • • 發佈:2018-12-12
#傳入的是真值標籤和預測標籤 def bbox_iou(bbox_a, bbox_b): print bbox_a.shape print bbox_b.shape if bbox_a.shape[1] != 4 or bbox_b.shape[1] != 4: raise IndexError # top left 這邊是計算了如圖上第一幅的重疊左下角座標值(x,y) tl = np.maximum(bbox_a[:, None, :2], bbox_b[:, :2]) # bottom right 這邊是計算了如圖上第一幅的重疊左上角座標值ymax和右下角座標值xmax br = np.minimum(bbox_a[:, None, 2:], bbox_b[:, 2:]) print br print tl.shape #np.prod 給定軸數值的乘積 相減就得到高和寬 然後相乘 area_i = np.prod(br - tl, axis=2) * (tl < br).all(axis=2)#重疊部分面積 area_a = np.prod(bbox_a[:, 2:] - bbox_a[:, :2], axis=1) area_b = np.prod(bbox_b[:, 2:] - bbox_b[:, :2], axis=1) return area_i / (area_a[:, None] + area_b - area_i)