LeetCode刷題338. Counting Bits
題目描述:
Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array.
Example 1:
Input: 2
Output: [0,1,1]
Example 2:
Input: 5 Output: [0,1,1,2,1,2]
題目大意:計算0-num中每個數所對應的二進位制中1的個數
解題思路:簡單粗暴,利用Java已有的API直接解決
class Solution {
public int[] countBits(int num) {
int[] arr = new int[num+1];
for(int i=0;i<num+1;i++){
arr[i] = Integer.bitCount(i);
}
return arr;
}
}
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