ZOJ-2060 Fibonacci Again(斐波那契找規律,水題)
阿新 • • 發佈:2018-12-15
ZOJ Problem Set - 2060
Fibonacci Again
Time Limit: 2 Seconds Memory Limit: 65536 KB
There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2)
Input Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000)
Output Print the word "yes" if 3 divide evenly into F(n). Print the word "no" if not.
Sample Input 0 1 2 3 4 5
Sample Output no no yes no no no
打表找規律就好了。
#include<iostream> using namespace std; int main() { int n ; while(cin>>n) { if(n%4 == 2) cout<<"yes"<<endl; else cout<<"no"<<endl; } return 0; }