C. Letters

There are $n$ dormitories in Berland State University, they are numbered with integers from $1$ to $n$. Each dormitory consists of rooms, there are $a_i$ rooms in $i$-th dormitory. The rooms in $i$-th dormitory are numbered from $1$ to $a_i$.

A postman delivers letters. Sometimes there is no specific dormitory and room number in it on an envelope. Instead of it only a room number among all rooms of all $n$

n dormitories is written on an envelope. In this case, assume that all the rooms are numbered from $1$ to $a_1+a_2+\cdots +a_n$ and the rooms of the first dormitory go first, the rooms of the second dormitory go after them and so on.

For example, in case $n=2$, $a_1=3$ and $a_2=5$ an envelope can have any integer from $1$

1 to $8$ written on it. If the number $7$ is written on an envelope, it means that the letter should be delivered to the room number $4$ of the second dormitory.

For each of $m$ letters by the room number among all $n$ dormitories, determine the particular dormitory and the room number in a dormitory where this letter should be delivered.

Input

The first line contains two integers $n$ and $m$ $(1\le n,m\le 2\cdot {10}^5)$ — the number of dormitories and the number of letters.

The second line contains a sequence $a_1,a_2,\dots ,a_n$ $(1\le a_i\le {10}^{10})$, where $a_i$ equals to the number of rooms in the $i$-th dormitory. The third line contains a sequence $b_1,b_2,\dots ,b_m$ $(1\le b_j\le a_1+a_2+\cdots +a_n)$, where $b_j$ equals to the room number (among all rooms of all dormitories) for the $j$-th letter. All $b_j$ are given in increasing order.

Output

Print $m$ lines. For each letter print two integers $f$ and $k$ — the dormitory number $f$ $(1\le f\le n)$ and the room number $k$ in this dormitory $(1\le k\le a_f)$ to deliver the letter.

ExamplesinputCopy

3 6
10 15 12
1 9 12 23 26 37

outputCopy

1 1
1 9
2 2
2 13
3 1
3 12

inputCopy

2 3
5 10000000000
5 6 9999999999

outputCopy

1 5
2 1
2 9999999994

程式碼：

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
int m = scan.nextInt();
long[] sum = new long[n];
sum[0] = scan.nextLong();
for(int i = 1; i < n; i++) sum[i] = sum[i-1] + scan.nextLong();
int ans = 0;
for(int i = 0; i < m; i++){
long t = scan.nextLong();
while(t>sum[ans]) ans++;

System.out.print((ans+1)+" ");
if(ans == 0){
System.out.println(t);
}else{
System.out.println(t-sum[ans-1]);
}
}
}
}