給一個骰子6個面編號，左面為1，右面為2， 前面為3， 後面為4， 上面為5，下面為6

有4種旋轉方式：

’L‘：往左旋轉90度

’R‘：往右旋轉90度

’F‘：往前旋轉90度

’B‘：往後旋轉90度

’A‘：順時針旋轉90度

’C‘：逆時針旋轉90度

求在進行多次上述操作後，左右前後上下面的標號為多少？

serial = {'left':1, 'right':2, 'front':3, 'back':4, 'up':5, 'down':6}
a = input("enter a number:\n")
for c in a:
    if c == 'L':
        left_orig, right_orig = serial['left'], serial['right']
        down_orig, up_orig = serial['down'], serial['up']
        serial['left'], serial['right'] = up_orig, down_orig
        serial['down'], serial['up'] = left_orig, right_orig
    if c == 'R':
        left_orig, right_orig = serial['left'], serial['right']
        down_orig, up_orig = serial['down'], serial['up']
        serial['left'], serial['right'] = down_orig, up_orig
        serial['down'], serial['up'] = right_orig, left_orig

    if c == 'F':
        front_orig, back_orig = serial['front'], serial['back']
        down_orig, up_orig = serial['down'], serial['up']
        serial['front'], serial['back'] = up_orig, down_orig
        serial['down'], serial['up'] = front_orig, back_orig
    if c == 'B':
        front_orig, back_orig = serial['front'], serial['back']
        down_orig, up_orig = serial['down'], serial['up']
        serial['front'], serial['back'] = down_orig, up_orig
        serial['down'], serial['up'] = back_orig, front_orig

    if c == 'A':
        front_orig, back_orig = serial['front'], serial['back']
        left_orig, right_orig = serial['left'], serial['right']
        serial['front'], serial['back'] = right_orig, left_orig
        serial['left'], serial['right'] = front_orig, back_orig
    if c == 'B':
        front_orig, back_orig = serial['front'], serial['back']
        left_orig, right_orig = serial['left'], serial['right']
        serial['front'], serial['back'] = left_orig, right_orig
        serial['left'], serial['right'] = back_orig, front_orig

for key in serial:
    print(serial[key], end='')