1. 程式人生 > >BZOJ 2212: [Poi2011]Tree Rotations 線段樹合併

BZOJ 2212: [Poi2011]Tree Rotations 線段樹合併

Byteasar the gardener is growing a rare tree called Rotatus Informatikus. It has some interesting features: The tree consists of straight branches, bifurcations and leaves. The trunk stemming from the ground is also a branch. Each branch ends with either a bifurcation or a leaf on its top end. Exactly two branches fork out from a bifurcation at the end of a branch - the left branch and the right branch. Each leaf of the tree is labelled with an integer from the range . The labels of leaves are unique. With some gardening work, a so called rotation can be performed on any bifurcation, swapping the left and right branches that fork out of it. The corona of the tree is the sequence of integers obtained by reading the leaves' labels from left to right. Byteasar is from the old town of Byteburg and, like all true Byteburgers, praises neatness and order. He wonders how neat can his tree become thanks to appropriate rotations. The neatness of a tree is measured by the number of inversions in its corona, i.e. the number of pairs(I,j), (1< = I < j < = N ) such that(Ai>Aj) in the corona(A1,A2,A3…An). 

 The original tree (on the left) with corona(3,1,2) has two inversions. A single rotation gives a tree (on the right) with corona(1,3,2), which has only one inversion. Each of these two trees has 5 branches. Write a program that determines the minimum number of inversions in the corona of Byteasar's tree that can be obtained by rotations.

現在有一棵二叉樹,所有非葉子節點都有兩個孩子。在每個葉子節點上有一個權值(有n個葉子節點,滿足這些權值為1..n的一個排列)。可以任意交換每個非葉子節點的左右孩子。
要求進行一系列交換,使得最終所有葉子節點的權值按照遍歷序寫出來,逆序對個數最少。