洛谷P2447 [SDOI2010]外星千足蟲(異或方程組)
阿新 • • 發佈:2019-02-09
找到 art pre pro code main getc earth getchar()
題意
題目鏈接
Sol
異或高斯消元的板子題。
bitset優化一下,復雜度\(O(\frac{nm}{32})\)
找最優解可以考慮高斯消元的過程,因為異或的特殊性質,每次向下找的時候找到第一個1然後交換就行,這樣顯然是最優的
#include<bits/stdc++.h> using namespace std; const int MAXN = 2001; inline int read() { char c = getchar(); int x = 0, f = 1; while(c < '0' || c > '9') {if(c == '-') f = -1; c = getchar();} while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar(); return x * f; } int N, M; bitset<MAXN> b[MAXN]; void Gauss() { int ans = 0; for(int i = 1; i <= N; i++) { int j = i; while(!b[j][i] && j < M + 1) j++; if(j == M + 1) {puts("Cannot Determine"); return ;} ans = max(ans, j); swap(b[i], b[j]); for(int j = 1; j <= M; j++) { if(i == j || !b[j][i]) continue; b[j] ^= b[i]; } } printf("%d\n", ans); for(int i = 1; i <= N; i++) puts(!b[i][N + 1] ? "Earth" : "?y7M#"); } int main() { N = read(); M = read(); for(int i = 1; i <= M; i++) { string s; cin >> s; b[i][N + 1] = read(); for(int j = 1; j <= N; j++) b[i][j] = (s[j - 1] == '0' ? 0 : 1); } Gauss(); return 0; }
洛谷P2447 [SDOI2010]外星千足蟲(異或方程組)