BJ模擬(1) D1T1 計數
阿新 • • 發佈:2019-02-15
#include #include #include #include #include #include #include using namespace std; inline char read() { static const int IN_LEN = 1024 * 1024; static char buf[IN_LEN], *s, *t; if (s == t) { t = (s = buf) + fread(buf, 1, IN_LEN, stdin); if (s == t) return -1; } return *s++; } template inline bool R(T &x) { static char c; static bool iosig; for (iosig = false, c = read(); !isdigit(c); c = read()) { if (c == -1) return false; if (c == '-') iosig = true; } for (x = 0; isdigit(c); c = read()) x = (x << 3) + (x << 1) + (c ^ '0'); if (iosig) x = -x; return true; } const int OUT_LEN = 1024 * 1024; char obuf[OUT_LEN], *oh = obuf; inline void writechar(char c) { if (oh == obuf + OUT_LEN) fwrite(obuf, 1, oh - obuf, stdout), oh = obuf; *oh++ = c; } template inline void W(T x) { static int buf[30], cnt; if (!x) writechar(48); else { if (x < 0) writechar('-'), x = -x; for (cnt = 0; x; x /= 10) buf[++cnt] = x % 10 + 48; while (cnt) writechar(buf[cnt--]); } } inline void flush() { fwrite(obuf, 1, oh - obuf, stdout); } const int MAXN = 2010; const int mod = 1e9 + 7; int C[MAXN][MAXN], f[MAXN], g[MAXN]; int a, b, c, d; inline void init(int a, int b, int *f) { if (a < b) swap(a, b); if (!a) return (void)(f[0] = 1); else if (!b) return (void)(f[a] = 1); for (int i = 0; i < 4; ++i) { int c = i + 1 >> 1; for (int j = 0; j <= min(b - c, a - 1); ++j) { int k = (a - 1 - j) + (b - c - j); int temp = 1LL * C[a - 1][j] * C[b - 1][j + c - 1] % mod; for (int l = k + 1; l <= a + b; ++l) f[l] = (f[l] + 1LL * C[a + b - 1 - k][l - k - 1] * temp) % mod; } } } int main() { // freopen("in.in", "r", stdin); R(a), R(b), R(c), R(d); for (int i = 0; i <= MAXN - 5; ++i) C[i][0] = C[i][i] = 1; for (int i = 0; i <= MAXN - 5; ++i) for (int j = 1; j <= i - 1; ++j) C[i][j] = (C[i - 1][j - 1] + C[i - 1][j]) % mod; init(a, b, f), init(c, d, g); int ans = 0; for (int i = 0; i <= a + b; ++i) { ans = (ans + 2LL * f[i] * g[i] + 1LL * f[i] * g[i + 1]) % mod; if (i) ans = (ans + 1LL * f[i] * g[i - 1]) % mod; } ans = (ans % mod + mod) % mod; W(ans), flush(); return 0; }