本文例項為大家分享了C語言編寫五子棋遊戲的具體程式碼，供大家參考，具體內容如下

一、構建棋盤

首先可以用一個二維陣列來構建棋盤，下標表示位置，內容表示黑子白子或者空位。當陣列內容為1時，該位置為白字，當陣列為0時，該位置為白子，空位輸出+

int w[11][11],flag = 0;
 int a,b;
 
 for (int k = 0; k < 11; k++)
   printf("第%d列\t",k);
  printf("\n");
  for (int i = 0; i < 11; i++) {
   for (int j = 0; j < 11; j++) {
    if (w[i][j] == 0) printf("黑\t");
    else if (w[i][j] == 1) printf("白\t");
    else printf("+\t");
   }
   printf("第%d行\n\n",i);
  }

二、判斷位置超範圍與錯誤輸入

當輸入的棋子座標超出範圍或者該位置已經存在棋子，則再次輸入棋子座標。其中flag作為標誌作為判別黑手白手的標誌。

if (flag == 0) {
   printf("黑色下棋\n");
   scanf("%d %d",&a,&b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出範圍，請重新輸入：");
    scanf("%d %d",&b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)   
   {
    printf("此位置已有棋子，請重新輸入：");
    scanf("%d %d",&b);
   }
   flag = 1;
   w[a][b] = 0;
  }
  else {
   printf("白色下棋\n");
   scanf("%d %d",&b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)
   {
    printf("此位置已有棋子，請重新輸入：");
    scanf("%d %d",&b);
   }

三、判斷勝負

在五子棋中，出現五個棋子排成一排或者一列或者斜排即可判為勝出。每當落下一個棋子，對該棋子前後上下斜排五個棋子進行判別，超過五個連續的一樣顏色的棋子則勝出。

int A = 1,B = 1,jieguo = 0,C = 1,D = 1;
  int x = 1,y = 1,m = 1,n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋勝利標誌
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標誌
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }

程式完成

四、演示結果

五、原始碼

int main() {
 int w[11][11],b;
 while (1) {
  if (flag == 0) {
   printf("黑色下棋\n");
   scanf("%d %d",&b);
   }
   flag = 0;
   w[a][b] = 1;
  }
  
  int A = 1,n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋勝利標誌
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標誌
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }
 
  for (int k = 0; k < 11; k++)
   printf("第%d列\t",i);
  }
  if (jieguo == 1) {
   printf("白棋勝利");
   break;
  }
  if (jieguo == 2) {
   printf("黑棋勝利");
   break;
  }
 }
 return 0;
}

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