leetcode124. Binary Tree Maximum Path Sum
class Solution: def __init__(self): self.res = -sys.maxsize # 主體就是後序遍歷 def maxPathSum(self, root): if root is None: return 0 self.helper(root) return self.res # 結果在這個類成員變數裡面 def helper(self, root): if root is None: return 0 left = max(0, self.helper(root.left)) right = max(0, self.helper(root.right)) self.res = max(self.res, left + right + root.val) # 在此處進行處理, 由於要儲存在一個變數裡, 定義了init函式 return max(left, right) + root.val
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leetcode124. Binary Tree Maximum Path Sum
class Solution: def __init__(self): self.res = -sys.maxsize # 主體就是後序遍歷 def maxPathSum(self, root): if
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又是一道好題啊。難點在於如何根據題意設計DFS過程。想一想如何求得由這個節點向下的路徑最大值。這個節點的值必然包括,左邊的值是max(0,l),右邊的是max(0,r)。所以設定helper函式是求包括這個節點在內的最大單邊路徑和,不能直接設定為最大雙邊路徑和(這樣會分岔不符合題意)。
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