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kd樹的實現(python)

當前的實現針對的是二維空間, 程式碼可執行

T = np.array([(2,3),(5,4),(9,6),(4,7),(8,1),(7,2)])
#T = np.array([(3,3),(2,2),(1,2)])
#plt.scatter(T[:,0], T[:,1])

def crt_tree(T, i):
    if len(T)==1:
        return Node(T[0])
    if len(T)==0:
        return None
    dim = T.shape[1]
    axis = i % dim
    #T空間的中間個數
    midPos = T.shape[0
]//2 #T的從大到小的專案的排列的索引 indices = T[:,axis].argsort(0) midItemPos = indices[T.shape[0]//2] node = Node(T[midItemPos]) leftT = T[indices[:midPos]] rightT = T[indices[midPos+1:]] node.left = crt_tree(leftT, i+1) node.right = crt_tree(rightT, i+1) return node t = crt_tree(T, 0
) pre_traversal(t) print(T) print(T.argsort(0))