1. 程式人生 > >1444: [Jsoi2009]有趣的遊戲

1444: [Jsoi2009]有趣的遊戲

while per gif getchar() names 一次 node bfs bre

1444: [Jsoi2009]有趣的遊戲

鏈接

分析:

  如果一個點回到0號點,那麽會使0號點的概率增加,而0號點的概率本來是1,不能增加,所以這題用期望做。

  設$x_i$表示經過i的期望次數,然後初始可以知道$x_0=0$,又因為末尾節點只會經過一次,所以末尾節點的概率就是期望。

  然後建出AC自動機,高斯消元。

  參考sengxian

代碼:

Gauss

技術分享圖片
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<iostream>
#include
<cmath> #include<cctype> #include<set> #include<queue> #include<vector> #include<map> using namespace std; typedef long long LL; inline int read() { int x=0,f=1;char ch=getchar();for(;!isdigit(ch);ch=getchar())if(ch==-)f=-1; for(;isdigit(ch);ch=getchar())x=x*10
+ch-0;return x*f; } const int N = 500; const double eps = 1e-10; int ch[N][26], val[N], fail[N], id[N], q[N], Index; int n, L, m; char s[N]; double A[N][N], p[N]; void Insert(int x) { int now = 0; for (int i = 0; i < L; ++i) { int c = s[i] - A; if (!ch[now][c]) ch[now][c] = ++Index; now
= ch[now][c]; } val[now] = 1, id[x] = now; } void bfs() { int L = 1, R = 0; for (int c = 0; c < m; ++c) if (ch[0][c]) q[++R] = ch[0][c]; while (L <= R) { int u = q[L ++]; for (int c = 0; c < m; ++c) { int v = ch[u][c]; if (!v) ch[u][c] = ch[fail[u]][c]; else { fail[v] = ch[fail[u]][c]; val[v] |= val[fail[v]]; q[++R] = v; } } } } bool Gauss(int n) { for (int k = 0; k <= n; ++k) { int r = k; for (int i = k + 1; i <= n; ++i) if (A[i][k] > A[r][k]) r = k; if (r != k) for (int j = 0; j <= n + 1; ++j) swap(A[r][j], A[k][j]); for (int i = k + 1; i <= n; ++i) { if (fabs(A[i][k]) > eps) { double t = A[i][k] / A[k][k]; for (int j = 0; j <= n + 1; ++j) A[i][j] -= A[k][j] * t; } } } for (int i = n; i >= 0; --i) { for (int j = i + 1; j <= n; ++j) A[i][n + 1] -= A[j][n + 1] * A[i][j]; A[i][n + 1] /= A[i][i]; } return 1; } int main() { n = read(), L = read(), m = read(); for (int i = 0; i < m; ++i) { int u = read(), v = read(); p[i] = 1.0 * u / v; } int cnt = 0; for (int i = 0; i < n; ++i) { scanf("%s", s); for (int j = 0; j < L; ++j) if (p[s[j] - A] <= eps) { cnt ++; break; } Insert(i); } if (cnt == n) { for (int i = 1; i <= n; ++i) puts("0.00"); return 0; } bfs(); A[0][Index + 1] = -1; for (int i = 0; i <= Index; ++i) { A[i][i] = -1.0; if (val[i]) continue; for (int c = 0; c < m; ++c) A[ch[i][c]][i] += p[c]; } Gauss(Index); for (int i = 0; i < n; ++i) { double p = A[id[i]][Index + 1]; if (fabs(p) <= eps) puts("0.00"); else printf("%.2lf\n", p); } return 0; }
View Code

叠代+矩陣

技術分享圖片
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<iostream>
#include<cmath>
#include<cctype>
#include<set>
#include<queue>
#include<vector>
#include<map>
using namespace std;
typedef long long LL;

inline int read() {
    int x=0,f=1;char ch=getchar();for(;!isdigit(ch);ch=getchar())if(ch==-)f=-1;
    for(;isdigit(ch);ch=getchar())x=x*10+ch-0;return x*f;
}

const int N = 105;
struct Node { 
    double a[N][N]; 
    Node() { memset(a, 0, sizeof(a)); } 
} A;
int ch[N][26], val[N], fail[N], id[N], q[N], Index;
int n, L, m;
char s[N];
double p[N];

Node operator * (const Node &A,const Node &B) {
    Node C;
    for (int k = 0; k <= Index; ++k)
        for (int i = 0; i <= Index; ++i)     
            for (int j = 0; j <= Index; ++j) 
                C.a[i][j] += A.a[i][k] * B.a[k][j];
    return C;
}
void Insert(int x) {
    int now = 0;
    for (int i = 0; i < L; ++i) {
        int c = s[i] - A;
        if (!ch[now][c]) ch[now][c] = ++Index;
        now = ch[now][c];
    }
    val[now] = 1, id[x] = now;
}
void bfs() {
    int L = 1, R = 0;
    for (int c = 0; c < m; ++c) if (ch[0][c]) q[++R] = ch[0][c];
    while (L <= R) {
        int u = q[L ++]; 
        for (int c = 0; c < m; ++c) {
            int v = ch[u][c];
            if (!v) ch[u][c] = ch[fail[u]][c];
            else {
                fail[v] = ch[fail[u]][c];
                val[v] |= val[fail[v]];
                q[++R] = v;
            }
        }
    }
}
int main() {
    n = read(), L = read(), m = read();
    for (int i = 0; i < m; ++i) {
        int u = read(), v = read();
        p[i] = 1.0 * u / v;
    }
    for (int i = 0; i < n; ++i) {
        scanf("%s", s);
        Insert(i);
    }
    bfs();
    for (int i = 0; i <= Index; ++i) {
        if (val[i]) A.a[i][i] = 1;
        else for (int c = 0; c < m; ++c) A.a[i][ch[i][c]] += p[c];
    }
    for (int i = 1; i <= 50; ++i) A = A * A;
    for (int i = 0; i < n; ++i) printf("%.2lf\n", A.a[0][id[i]]);
    return 0;
}
View Code

1444: [Jsoi2009]有趣的遊戲