LintCode 110---最小路徑和
阿新 • • 發佈:2019-05-08
long numbers ram pub public div spa sts nim
public class Solution { /** * @param grid: a list of lists of integers * @return: An integer, minimizes the sum of all numbers along its path */ public int minPathSum(int[][] grid) { if(grid == null || grid.length == 0 || grid[0].length == 0) return -1;int[][] f = new int[grid.length][grid[0].length]; f[0][0] = grid[0][0]; for(int i = 1; i < grid.length; i++){ f[i][0] = f[i-1][0] + grid[i][0]; } for(int i = 1; i < grid[0].length; i++){ f[0][i] = f[0][i-1] + grid[0][i]; } for(int i = 1; i < grid.length; i++){for(int j = 1; j < grid[0].length; j++){ f[i][j] = Math.min(f[i][j-1],f[i-1][j]) + grid[i][j]; } } return f[grid.length-1][grid[0].length-1]; } }
LintCode 110---最小路徑和