Leetcode137 Single Number II
136題的加強版,有三個相同數字出現了。
class Solution { public int singleNumber(int[] nums) { if(nums.length==1) return nums[0]; int ones=0,twos=0; for(int i=0;i<nums.length;i++){ ones=(ones^nums[i])&~twos; twos=(twos^nums[i])&~ones; } returnones; } }
0ms,100%
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136題的加強版,有三個相同數字出現了。 class Solution { public int singleNumber(int[] nums) { if(nums.length==1) return nums[0]; int ones=0,twos=0;
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