LeetCode-電話號碼的字母組合
阿新 • • 發佈:2019-01-04
給定一個僅包含數字 2-9
的字串,返回所有它能表示的字母組合。
給出數字到字母的對映如下(與電話按鍵相同)。注意 1 不對應任何字母。
示例:
輸入:"23" 輸出:["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
說明:
儘管上面的答案是按字典序排列的,但是你可以任意選擇答案輸出的順序。
class Solution { public List<String> letterCombinations(String digits) { ArrayList<String> list = new ArrayList<>(); if(digits==null||digits.length()==0) { return list; } String[] phoneNumbers = {" ", " ", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; dfsPhoneNumbers(digits,0,phoneNumbers,list,new StringBuffer()); return list; } private void dfsPhoneNumbers(String digits,int index, String[] phoneNumbers, ArrayList<String> list,StringBuffer buffer) { // TODO Auto-generated method stub if(index==digits.length()) { list.add(buffer.toString()); return; } String phoneNumberString = phoneNumbers[digits.charAt(index)-'0']; for(int i=0;i<phoneNumberString.length();++i) { buffer.append(phoneNumberString.charAt(i)); dfsPhoneNumbers(digits, index+1, phoneNumbers, list, buffer); buffer.deleteCharAt(buffer.length()-1); } } }