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PAT 1020. 月餅

#include <stdio.h>


int main() {
int N, D, i, j, max_i;
float sum, remain, max;
float num[4][1000];
scanf("%d %d", &N, &D);
for(i = 0; i < 2; i ++) {
for(j = 0; j < N; j ++) {
scanf("%f", &num[i][j]);
}
}
for(i = 0; i < N; i ++) {
num[2][i] = num[1][i] / num[0][i];
num[3][i] = 0;
}
sum = 0;
remain = D;
while(1) {
max = 0;
max_i = -1;
for(i = 0; i < N; i ++) {
if(num[3][i] == 0 && max < num[2][i]) {
max = num[2][i];
max_i = i;
}
}
if(max_i == -1) {
break;
}
if(remain <= num[0][max_i]) {

sum = sum + remain / (1.0 * num[0][max_i]) * num[1][max_i];
break;
} else {
sum = sum + num[1][max_i];
remain = remain - num[0][max_i];
num[3][max_i] = 1;
}
}
printf("%.2f\n", sum);
return 0;
}