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java原碼補碼反碼關係解析

本文為大家解析了java原碼補碼反碼的關係,供大家參考,具體內容如下

原碼:不管源資料是十進位制還是十六進位制,統統將數字轉成二進位制形式

反碼:把原碼的二進位制統統反過來,0變成1,1變成0

補碼:負數的反碼加1,就是負數的補碼

例子1:

十進位制整數 -5,-5的原碼101,-5的反碼1,010,-5的補碼1,011,
所以,-5的反碼是-2,-5的補碼是-3,其中前面的"1,",表示正數負數

例子2:

十六進位制 -ff9B
原碼 11111111111110011011
反碼 00000000000001100100 十進位制100
補碼 00000000000001100100 十進位制101
原來正確的操作流程是,把16進位制ff9B轉成2進位制,然後直接反碼,再算補碼,就是溫度資料

程式碼驗證:

package comtest.example.admin.znum;
 
/**
 * Created by wrs on 2019/6/5,16:25
 * projectName: Testz
 * packageName: comtest.example.admin.znum
 * 輸入一個真值(整數)求它的原碼,反碼,補碼
 */
 
 
import java.util.Scanner;
 
 
public class Test {
 public static void main(String[] args) {
 System.out.println("True value--> original code");
 System.out.println("Please enter an integer!!!!!");
 Scanner sc = new Scanner(System.in);
 int value = sc.nextInt();
 StringBuilder syuan = new StringBuilder();
 if (value > 0) {
 String Bvalue = Integer.toBinaryString(value);//將一個整數轉換成字串型別的二進位制數
 int n = Bvalue.length(); //二進位制的數字的個數n
 syuan.append("0,");
 syuan.append(Bvalue);
 System.out.println("Original code " + syuan); //原碼
 System.out.println("Complement code " + syuan); //補碼
 System.out.println("Inverse code " + syuan); //反碼
 
// System.out.println("二進位制數的n "+n);
 } else if (value < 0) {
 int value2 = Math.abs(value); //負數的絕對值
 int value3 = value2 - 1; //減一求反,求補碼
 String Bvalue = Integer.toBinaryString(value2);
 String BFvalue = Integer.toBinaryString(~value2);
 int n = Bvalue.length();
 String str = BFvalue.substring(BFvalue.length() - n); //擷取反碼的後幾個數
 syuan.append("1,");
 syuan.append(Bvalue);
 System.out.println("Original code is :" + syuan);
 System.out.println("Inverse code is :1," + str);
 String BBvalue = Integer.toBinaryString(~value3);
 String str3 = BBvalue.substring(BFvalue.length() - n);
 System.out.println("Complement code is :1," + str3);
 } else {
 System.out.println("0 Original code is not only");
 System.out.println("[+0]riginal code 00.....0");
 System.out.println("[-0]riginal code 10.....0");
 System.out.println("--------------------------------------------");
 System.out.println("0 Complement code is not only");
 System.out.println("[+0]和[-0] Complement code 00.....0");
 System.out.println("---------------------------------------------");
 System.out.println("0 Inverse code is not only");
 System.out.println("[+0]Inverse code00..........0");
 System.out.println("[-0]Inverse code11..........1");
 }
 System.out.println("-------------------------------------------------");
 
 }
}

執行效果:

-------------------------------------------------
True value--> original code
Please enter an integer!!!!!
-65435
Original code is :1,1111111110011011
Inverse code is :1,0000000001100100
Complement code is :1,0000000001100101
-------------------------------------------------

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