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Matlab的離散點曲線導數曲率數值模擬方法

clc; clear all; close all;
x0 = linspace(0, 1);
y0 = sin(x0).*cos(x0);
h = abs(diff([x0(2), x0(1)]));
% 模擬一階導
figure; box on; hold on;
ythe1 = cos(x0).^2 - sin(x0).^2; %理論一階導
yapp1 = gradient(y0, h); %matlab數值近似
plot(x0, ythe1, '.');
plot(x0, yapp1, 'r');
legend('理論值', '模擬值');
title('模擬一階導');
% 模擬二階導
figure; box on; hold on;

ythe2 = (-4)*cos(x0).*sin(x0); %理論二階導
yapp2 = 2*2*del2(y0, h); %matlab數值近似
plot(x0, ythe2,'.');
plot(x0, yapp2,'r');
legend('理論值', '模擬值');
title('模擬二階導');
% 模擬曲率
syms x y
y = sin(x)*cos(x);
yd2 = diff(y, 2);
yd1 = diff(y, 1);
k = abs(yd2)/(1+yd1^2)^(3/2);
k1 = subs(k, x, x0);
k2 = abs(yapp2)./(1+yapp1.^2).^(3/2);
figure; box on; hold on;
plot(x0, k1, '.');
plot(x0, k2, 'r');
legend('理論值', '模擬值', 'Location', 'NorthWest');
title('模擬曲率');

效果:

未命名.bmp (595.01 KB)

2010-3-7 17:01


未命名1.bmp (574.92 KB)

2010-3-7 17:01