LeetCode 36. 有效的數獨
阿新 • • 發佈:2021-02-02
技術標籤:java
判斷一個 9x9 的數獨是否有效。只需要根據以下規則,驗證已經填入的數字是否有效即可。
數字 1-9 在每一行只能出現一次。
數字 1-9 在每一列只能出現一次。
數字 1-9 在每一個以粗實線分隔的 3x3 宮內只能出現一次。
示例 1:
輸入:
[
["5","3",".",".","7",".",".",".","."],
["6","." ,".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6" ,".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".","." ,"6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
輸出: true
示例 2:
輸入:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
輸出: false
解釋: 除了第一行的第一個數字從 5 改為 8 以外,空格內其他數字均與 示例1 相同。
但由於位於左上角的 3x3 宮內有兩個 8 存在, 因此這個數獨是無效的。
說明:
一個有效的數獨(部分已被填充)不一定是可解的。
只需要根據以上規則,驗證已經填入的數字是否有效即可。
給定數獨序列只包含數字 1-9 和字元 '.' 。
給定數獨永遠是 9x9 形式的。
來源:力扣(LeetCode)
連結:https://leetcode-cn.com/problems/valid-sudoku
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class Solution {
public boolean isValidSudoku(char[][] board) {
Map<Character,Boolean> row=new HashMap<>();
Map<Character,Boolean> col=new HashMap<>();
Map<Character,Boolean> box[]=new HashMap[9];
for(int i=0;i<9;i++) box[i]=new HashMap<Character, Boolean>();
//對所有行進行判斷
for(int i=0;i<9;i++){
row.clear();
for(int j=0;j<9;j++){
if(board[i][j]=='.') continue;
if(row.containsKey(board[i][j])) return false;
row.put(board[i][j], true);
}
}
//對所有列進行判斷
for(int i=0;i<9;i++){
col.clear();
for(int j=0;j<9;j++){
if(board[j][i]=='.') continue;
if(col.containsKey(board[j][i])) return false;
col.put(board[j][i], true);
}
}
//對粗線分割的九宮格進行判斷
for(int i=0;i<9;i++){
for(int j=0;j<9;j++){
if(board[i][j]=='.') continue;
int boxIndex=(i/3)*3+j/3;
if(box[boxIndex].containsKey(board[i][j])) return false;
box[boxIndex].put(board[i][j], true);
}
}
return true;
}
}