威爾遜定理 HDU2973 YAPTCHA
阿新 • • 發佈:2017-07-11
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However, the test turned out difficult for some math PhD students and even for some professors. Therefore, the math department wants to write a helper program which solves this task (it is not irrational, as they are going to make money on selling the program).
The task that is presented to anyone visiting the start page of the math department is as follows: given a natural n, compute
where [x] denotes the largest integer not greater than x.
Sample Output
0
1
1
2
2
2
2
3
3
4
28
207
1609
YAPTCHA
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 930 Accepted Submission(s): 491
However, the test turned out difficult for some math PhD students and even for some professors. Therefore, the math department wants to write a helper program which solves this task (it is not irrational, as they are going to make money on selling the program).
The task that is presented to anyone visiting the start page of the math department is as follows: given a natural n, compute
where [x] denotes the largest integer not greater than x.
Input The first line contains the number of queries t (t <= 10^6). Each query consist of one natural number n (1 <= n <= 10^6).
Output For each n given in the input output the value of Sn.
Sample Input 13 1 2 3 4 5 6 7 8 9 10 100 1000 10000
Source Central European Programming Contest 2008
Recommend lcy
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 #include<cmath> 6 using namespace std; 7 int t; 8 boolcheck[3000010]; 9 int num[1000010]; 10 void Eratosthenes(){ 11 check[0]=1; 12 check[1]=1; 13 for(int i=2;i<=sqrt(3000010);i++) 14 if(!check[i]) 15 for(int j=2*i;j<=3000010;j+=i) check[j]=1; 16 } 17 int main(){ 18 scanf("%d",&t); 19 Eratosthenes(); 20 for(int i=1;i<=1000000;i++) 21 if(check[3*i+7]) num[i]=num[i-1]; 22 else num[i]=num[i-1]+1; 23 int a; 24 for(int i=1;i<=t;i++){ 25 scanf("%d",&a); 26 printf("%d\n",num[a]); 27 } 28 return 0; 29 }
威爾遜定理 HDU2973 YAPTCHA